Menu Close

Find-maximum-of-n-such-that-n-2-n-1-is-factor-of-19n-2019-1-




Question Number 82514 by naka3546 last updated on 22/Feb/20
Find   maximum  of  n  such  that    n^2  + n + 1  is  factor  of  19n^(2019)  + 1 .
$${Find}\:\:\:{maximum}\:\:{of}\:\:{n}\:\:{such}\:\:{that}\:\: \\ $$$${n}^{\mathrm{2}} \:+\:{n}\:+\:\mathrm{1}\:\:{is}\:\:{factor}\:\:{of}\:\:\mathrm{19}{n}^{\mathrm{2019}} \:+\:\mathrm{1}\:. \\ $$
Commented by naka3546 last updated on 22/Feb/20
n  ∈  N
$${n}\:\:\in\:\:\mathbb{N} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *