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a-b-b-a-1-a-b-a-b-0-




Question Number 83477 by M±th+et£s last updated on 02/Mar/20
a^b +b^a =1   a=? , b=?  a≠b≠0
$${a}^{{b}} +{b}^{{a}} =\mathrm{1}\:\:\:{a}=?\:,\:{b}=? \\ $$$${a}\neq{b}\neq\mathrm{0} \\ $$
Commented by mr W last updated on 03/Mar/20
if a,b∈R, then i think there is no  solution for a≠b≠0.
$${if}\:{a},{b}\in{R},\:{then}\:{i}\:{think}\:{there}\:{is}\:{no} \\ $$$${solution}\:{for}\:{a}\neq{b}\neq\mathrm{0}. \\ $$

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