ln-cosx-dx- Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 149150 by mathdanisur last updated on 03/Aug/21 ∫ln(cosx)dx=? Answered by puissant last updated on 03/Aug/21 K=xln(cosx)+∫xtanxdx=xln(cosx)+∫x∑∞n=1∣B2n∣22n(22n−1)x2n−1(2n)!dx=xln(cosx)+∑∞n=1∣B2n∣22n(22n−1)(2n)!∫x2ndxsoit:I=xln(cosx)+∑∞n=1∣B2n∣22n(22n−1)(2n+1)!x2n+1+C……Lepuissant… Commented by mathdanisur last updated on 03/Aug/21 ThankYouSer Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 1-x-1-5-6-3-6-x-x-2-gt-1-1-x-1-Next Next post: lim-n-1-n-1-1-2-1-3-1-n- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.