Question Number 18153 by aplus last updated on 16/Jul/17
Commented by prakash jain last updated on 16/Jul/17
$$\mathrm{4}^{\mathrm{2}{x}} =\mathrm{2}×\mathrm{500}^{\mathrm{500}} \\ $$$$\mathrm{2}{x}\mathrm{log}\:\mathrm{4}=\mathrm{log}\:\mathrm{2}+\mathrm{500log}\:\mathrm{500} \\ $$$$\mathrm{3}=\frac{\mathrm{log}\:\mathrm{2}+\mathrm{500log}\:\mathrm{500}}{\mathrm{2log}\:\mathrm{4}}\approx\mathrm{1120}.\mathrm{973} \\ $$