Question Number 18415 by tawa tawa last updated on 20/Jul/17
$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{magnetic}\:\mathrm{field}\:\mathrm{produced}\:\mathrm{at}\:\mathrm{ground}\:\mathrm{level}\:\mathrm{by}\:\mathrm{a}\:\mathrm{15A}\:\mathrm{current} \\ $$$$\mathrm{flowing}\:\mathrm{in}\:\mathrm{a}\:\mathrm{long}\:\mathrm{horizontal}\:\mathrm{wire}\:\mathrm{suspended}\:\mathrm{at}\:\mathrm{a}\:\mathrm{height}\:\mathrm{of}\:\mathrm{7}.\mathrm{5m} \\ $$
Commented by tawa tawa last updated on 20/Jul/17
$$\mathrm{please}\:\mathrm{help}. \\ $$
Answered by diofanto last updated on 20/Jul/17
$${B}\:=\:\frac{\mu_{\mathrm{0}} {I}}{\mathrm{2}\pi{R}}\:=\:\frac{\mathrm{4}\pi\:×\:\mathrm{10}^{−\mathrm{7}} \:×\:\mathrm{15}}{\mathrm{2}\pi\:×\:\mathrm{7}.\mathrm{5}}\:=\:\mathrm{4}\:×\:\mathrm{10}^{−\mathrm{7}} \:\mathrm{T} \\ $$
Commented by tawa tawa last updated on 20/Jul/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$