Question Number 84407 by jagoll last updated on 12/Mar/20
$$\mathrm{dy}+\mathrm{2xy}\:\mathrm{dx}\:=\:\mathrm{xe}^{−\mathrm{x}^{\mathrm{2}} } \mathrm{y}^{\mathrm{3}} \:\mathrm{dx} \\ $$$$ \\ $$
Answered by john santu last updated on 13/Mar/20
dy-2xy-dx-xe-x-2-y-3-dx-