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log-3-25x-2-4-log-3-x-log-3-26x-2-17-x-10-




Question Number 84828 by john santu last updated on 17/Mar/20
log_3 (25x^2 −4)−log_3 (x) ≤ log_3 (26x^2 +((17)/x)−10)
$$\mathrm{log}_{\mathrm{3}} \left(\mathrm{25x}^{\mathrm{2}} −\mathrm{4}\right)−\mathrm{log}_{\mathrm{3}} \left(\mathrm{x}\right)\:\leqslant\:\mathrm{log}_{\mathrm{3}} \left(\mathrm{26x}^{\mathrm{2}} +\frac{\mathrm{17}}{\mathrm{x}}−\mathrm{10}\right) \\ $$
Commented by john santu last updated on 16/Mar/20
x > (2/5)
$$\mathrm{x}\:>\:\frac{\mathrm{2}}{\mathrm{5}} \\ $$

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