Question Number 19294 by mondodotto@gmail.com last updated on 08/Aug/17
Answered by mrW1 last updated on 08/Aug/17
$$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{2x}^{\mathrm{2}} +\mathrm{5x}+\mathrm{3} \\ $$$$=\mathrm{2}\left(\mathrm{x}^{\mathrm{2}} +\mathrm{2}×\frac{\mathrm{5}}{\mathrm{4}}\mathrm{x}+\frac{\mathrm{25}}{\mathrm{16}}\right)+\mathrm{3}−\frac{\mathrm{25}}{\mathrm{8}} \\ $$$$=\mathrm{2}\left(\mathrm{x}+\frac{\mathrm{5}}{\mathrm{4}}\right)^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{8}} \\ $$