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5-12i-5-12i-5-12i-5-12i-




Question Number 19433 by Tinkutara last updated on 11/Aug/17
(((√(5 + 12i)) + (√(5 − 12i)))/( (√(5 + 12i)) − (√(5 − 12i)))) =
5+12i+512i5+12i512i=
Answered by ajfour last updated on 11/Aug/17
=((((√(5+12i))+(√(5−12i)))^2 )/(24i))  =((10+2(√(25+144)))/(24i))=(3/(2i))=−(3/2)i .
=(5+12i+512i)224i=10+225+14424i=32i=32i.
Commented by Tinkutara last updated on 11/Aug/17
Thank you very much Sir!
ThankyouverymuchSir!

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