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x-3-y-3-3xy-2-dy-dx-




Question Number 85356 by jagoll last updated on 21/Mar/20
(x^3 +y^3 ) = 3xy^2  (dy/dx)
$$\left(\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} \right)\:=\:\mathrm{3xy}^{\mathrm{2}} \:\frac{\mathrm{dy}}{\mathrm{dx}} \\ $$
Answered by jagoll last updated on 21/Mar/20

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