Question Number 150968 by mathdanisur last updated on 17/Aug/21
Answered by dumitrel last updated on 17/Aug/21
$$\Sigma\frac{\left(\mathrm{2}{x}+{y}\right)\left(\mathrm{3}{x}^{\mathrm{2}} +{xy}+\mathrm{2}{y}^{\mathrm{2}} \right)}{\mathrm{2}{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }\leqslant\Sigma\mathrm{3}\left({x}+{y}\right)=\mathrm{6}\left({x}+{y}+{z}\right) \\ $$
Commented by mathdanisur last updated on 17/Aug/21
$$\mathrm{nice}\:\mathrm{Ser}\:\mathrm{thank}\:\mathrm{you} \\ $$