Question Number 21280 by gopikrishnan005@gmail.com last updated on 18/Sep/17
$${cosec}^{\mathrm{2}} \mathrm{67}^{\mathrm{0}} −{tan}^{\mathrm{2}} \mathrm{23}^{\mathrm{0}} = \\ $$
Answered by $@ty@m last updated on 18/Sep/17
$$\mathrm{1} \\ $$