A-heavy-iron-bar-of-weight-W-is-having-its-one-end-on-the-ground-and-the-other-on-the-shoulder-of-a-man-The-rod-makes-an-angle-with-the-horizontal-What-is-the-weight-experienced-by-the-man-

Question Number 21936 by Tinkutara last updated on 07/Oct/17

$$\mathrm{A}\:\mathrm{heavy}\:\mathrm{iron}\:\mathrm{bar}\:\mathrm{of}\:\mathrm{weight}\:{W}\:\mathrm{is}\:\mathrm{having} \\ $$$$\mathrm{its}\:\mathrm{one}\:\mathrm{end}\:\mathrm{on}\:\mathrm{the}\:\mathrm{ground}\:\mathrm{and}\:\mathrm{the}\:\mathrm{other} \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{shoulder}\:\mathrm{of}\:\mathrm{a}\:\mathrm{man}.\:\mathrm{The}\:\mathrm{rod} \\ $$$$\mathrm{makes}\:\mathrm{an}\:\mathrm{angle}\:\theta\:\mathrm{with}\:\mathrm{the}\:\mathrm{horizontal}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{weight}\:\mathrm{experienced}\:\mathrm{by}\:\mathrm{the} \\ $$$$\mathrm{man}? \\ $$

Answered by ajfour last updated on 07/Oct/17

$$\left({W}\mathrm{cos}\:\theta\right)\left({L}/\mathrm{2}\right)={FL} \\ $$$$\Rightarrow\:{F}=\frac{{W}\mathrm{cos}\:\theta}{\mathrm{2}}\:. \\ $$

Commented by ajfour last updated on 07/Oct/17

$${what}\:{if}\:\theta=\mathrm{90}°\:. \\ $$

Commented by Tinkutara last updated on 07/Oct/17

$$\mathrm{But}\:\mathrm{answer}\:\mathrm{is}\:\mathrm{given}\:\mathrm{independent}\:\mathrm{of}\:\theta. \\ $$

Commented by mrW1 last updated on 07/Oct/17

$$\mathrm{what}\:\mathrm{if}\:\mathrm{the}\:\mathrm{ground}\:\mathrm{is}\:\mathrm{smooth}? \\ $$

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