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Calculate-the-energy-emitted-when-electrons-of-1-g-atom-of-hydrogen-undergo-transition-giving-the-spectral-line-of-lowest-energy-in-the-visible-region-of-its-atomic-spectrum-R-H-1-1-10-7-m-1-




Question Number 22050 by Tinkutara last updated on 10/Oct/17
Calculate the energy emitted when  electrons of 1 g atom of hydrogen  undergo transition giving the spectral  line of lowest energy in the visible  region of its atomic spectrum  (R_H  = 1.1 × 10^7  m^(−1) , c = 3 × 10^8  ms^(−1) ,  h = 6.62 × 10^(−34)  Js)
$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{energy}\:\mathrm{emitted}\:\mathrm{when} \\ $$$$\mathrm{electrons}\:\mathrm{of}\:\mathrm{1}\:\mathrm{g}\:\mathrm{atom}\:\mathrm{of}\:\mathrm{hydrogen} \\ $$$$\mathrm{undergo}\:\mathrm{transition}\:\mathrm{giving}\:\mathrm{the}\:\mathrm{spectral} \\ $$$$\mathrm{line}\:\mathrm{of}\:\mathrm{lowest}\:\mathrm{energy}\:\mathrm{in}\:\mathrm{the}\:\mathrm{visible} \\ $$$$\mathrm{region}\:\mathrm{of}\:\mathrm{its}\:\mathrm{atomic}\:\mathrm{spectrum} \\ $$$$\left(\mathrm{R}_{\mathrm{H}} \:=\:\mathrm{1}.\mathrm{1}\:×\:\mathrm{10}^{\mathrm{7}} \:\mathrm{m}^{−\mathrm{1}} ,\:{c}\:=\:\mathrm{3}\:×\:\mathrm{10}^{\mathrm{8}} \:{ms}^{−\mathrm{1}} ,\right. \\ $$$$\left.{h}\:=\:\mathrm{6}.\mathrm{62}\:×\:\mathrm{10}^{−\mathrm{34}} \:\mathrm{Js}\right) \\ $$

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