Question Number 154274 by mathdanisur last updated on 16/Sep/21
$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}: \\ $$$$\mathrm{x}^{\mathrm{2}} \centerdot\mathrm{2}^{\boldsymbol{\mathrm{x}}} \left(\mathrm{x}^{\mathrm{4}} \centerdot\mathrm{4}^{\boldsymbol{\mathrm{x}}} \:+\:\mathrm{3}\centerdot\mathrm{15}^{\boldsymbol{\mathrm{x}}} \right)\:=\:\mathrm{125}^{\boldsymbol{\mathrm{x}}} \:-\:\mathrm{27}^{\boldsymbol{\mathrm{x}}} \\ $$
Commented by MJS_new last updated on 16/Sep/21
$${x}=\mathrm{0} \\ $$$${x}=\mathrm{1} \\ $$$${x}=\mathrm{2} \\ $$$$\left({x}=−\infty\right) \\ $$