Question Number 154734 by imjagoll last updated on 21/Sep/21
$$\:\begin{cases}{\mathrm{x}=\left(\mathrm{y}−\mathrm{2}\right)\left(\mathrm{y}+\mathrm{2}\right)}\\{\mathrm{y}=\left(\mathrm{z}−\mathrm{2}\right)\left(\mathrm{z}+\mathrm{2}\right)}\\{\mathrm{z}=\left(\mathrm{x}−\mathrm{2}\right)\left(\mathrm{x}+\mathrm{2}\right)}\end{cases}\:;\:\mathrm{x}\neq\mathrm{0},\:\mathrm{y}\neq\mathrm{0},\:\mathrm{z}\neq\mathrm{0} \\ $$$$\Rightarrow\:\mathrm{x}^{\mathrm{5}} +\mathrm{y}^{\mathrm{5}} +\mathrm{z}^{\mathrm{5}} \:=? \\ $$
Answered by MJS_new last updated on 21/Sep/21
$$\mathrm{not}\:\mathrm{unique} \\ $$