Question Number 89292 by student work last updated on 16/Apr/20
Answered by jagoll last updated on 16/Apr/20
$${x}+{y}\:=\:\mathrm{20}\:\left({i}\right) \\ $$$${y}+{z}\:=\:\mathrm{10}\:\left({ii}\right) \\ $$$${x}+{u}\:=\:\mathrm{24}\:\left({iii}\right) \\ $$$$\frac{{u}}{{z}}\:=\:\mathrm{7}\:\Rightarrow{u}\:=\:\mathrm{7}{z}\:\left({iv}\right) \\ $$$$\Rightarrow\mathrm{7}{z}+{x}\:=\:\mathrm{24} \\ $$$$\:\:\:\:\:\:{x}−{z}\:=\:\mathrm{10}\:\Rightarrow\begin{cases}{{z}\:=\:\frac{\mathrm{7}}{\mathrm{4}}}\\{{x}\:=\:\frac{\mathrm{47}}{\mathrm{4}}}\end{cases} \\ $$$$\begin{cases}{{y}\:=\:\frac{\mathrm{33}}{\mathrm{4}}}\\{{u}\:\:=\:\frac{\mathrm{49}}{\mathrm{4}}}\end{cases} \\ $$
Commented by student work last updated on 16/Apr/20
$${no}\:{u}\boldsymbol{\div}{z}=\mathrm{7} \\ $$