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P-X-299-318-standard-deviation-42-P-z-299-318-42-P-z-0-45-Is-it-P-z-0-45-P-0-45-lt-z-lt-0-44-If-not-how-to-find-P-z-0-45-




Question Number 23781 by alibhar last updated on 06/Nov/17
P(X=299), μ=318, standard deviation=42  P(z=((299−318)/(42)))  P(z=−0.45)    Is it P(z=−0.45)=P(−0.45<z<−0.44)?    If not, how to find P(z=−0.45)?
$${P}\left({X}=\mathrm{299}\right),\:\mu=\mathrm{318},\:{standard}\:{deviation}=\mathrm{42} \\ $$$${P}\left({z}=\frac{\mathrm{299}−\mathrm{318}}{\mathrm{42}}\right) \\ $$$${P}\left({z}=−\mathrm{0}.\mathrm{45}\right) \\ $$$$ \\ $$$${Is}\:{it}\:{P}\left({z}=−\mathrm{0}.\mathrm{45}\right)={P}\left(−\mathrm{0}.\mathrm{45}<{z}<−\mathrm{0}.\mathrm{44}\right)? \\ $$$$ \\ $$$${If}\:{not},\:{how}\:{to}\:{find}\:{P}\left({z}=−\mathrm{0}.\mathrm{45}\right)? \\ $$

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