Question Number 67662 by Rio Michael last updated on 29/Aug/19
$${please}\:{explain}\:{the}\:{fact}\:{that}\: \\ $$$$\int\frac{\mathrm{1}}{{x}}{dx}\:=\:{ln}\:{x}\:+\:{k} \\ $$
Commented by malwaan last updated on 29/Aug/19
$$\int\frac{{f}\:'\left({x}\right)}{{f}\left({x}\right)}{dx}\:={ln}\:\mid{f}\left({x}\right)\mid+\:{c} \\ $$$$\left({x}\right)'=\mathrm{1} \\ $$
Commented by Rio Michael last updated on 30/Aug/19
$${thank}\:{sir} \\ $$