Question Number 89632 by jagoll last updated on 18/Apr/20
$$\mathrm{y}\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}\:\mathrm{dx}\:+\:\mathrm{x}\sqrt{\mathrm{y}^{\mathrm{2}} −\mathrm{1}}\:\mathrm{dy}\:=\mathrm{0} \\ $$
Answered by john santu last updated on 18/Apr/20
