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Question-89741




Question Number 89741 by cindiaulia last updated on 19/Apr/20
Commented by jagoll last updated on 19/Apr/20
area = (1/2) ∣ determinant (((0     0)),((1     1)))+  determinant (((1      1)),(((2/5)  (8/5))))+  determinant ((((2/5)    (8/5))),((0       0)))∣  = (1/2) ∣ 0+(6/5)+0 ∣ = (3/5)
$$\mathrm{area}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\:\mid\begin{vmatrix}{\mathrm{0}\:\:\:\:\:\mathrm{0}}\\{\mathrm{1}\:\:\:\:\:\mathrm{1}}\end{vmatrix}+\:\begin{vmatrix}{\mathrm{1}\:\:\:\:\:\:\mathrm{1}}\\{\frac{\mathrm{2}}{\mathrm{5}}\:\:\frac{\mathrm{8}}{\mathrm{5}}}\end{vmatrix}+\:\begin{vmatrix}{\frac{\mathrm{2}}{\mathrm{5}}\:\:\:\:\frac{\mathrm{8}}{\mathrm{5}}}\\{\mathrm{0}\:\:\:\:\:\:\:\mathrm{0}}\end{vmatrix}\mid \\ $$$$=\:\frac{\mathrm{1}}{\mathrm{2}}\:\mid\:\mathrm{0}+\frac{\mathrm{6}}{\mathrm{5}}+\mathrm{0}\:\mid\:=\:\frac{\mathrm{3}}{\mathrm{5}} \\ $$

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