Question Number 89950 by student work last updated on 20/Apr/20
Commented by Tony Lin last updated on 20/Apr/20
$${a}=\mathrm{10},{b}=\mathrm{6},{c}=\sqrt{\mathrm{10}^{\mathrm{2}} −\mathrm{6}^{\mathrm{2}} }=\mathrm{8} \\ $$$${AA}^{'} =\mathrm{2}{a}=\mathrm{20} \\ $$$${BB}^{'} =\mathrm{2}{b}=\mathrm{12} \\ $$$${FF}^{'} =\mathrm{2}{c}=\mathrm{16} \\ $$$${AorA}'\left(\mathrm{10},\mathrm{0}\right)\:{A}^{'} {orA}\left(−\mathrm{10},\mathrm{0}\right) \\ $$$${BorB}'\left(\mathrm{0},\mathrm{6}\right)\:{B}^{'} {orB}\left(\mathrm{0},−\mathrm{6}\right) \\ $$$${CorC}'\left(\mathrm{8},\mathrm{0}\right)\:{C}^{'} {orC}\left(−\mathrm{8},\mathrm{0}\right) \\ $$$${I}\:{think}\:{you}\:{should}\:{enumerate}\: \\ $$$${the}\:{meaning}\:{of}\:{the}\:{following} \\ $$$${Don}'{t}\:{just}\:{post}\:{it} \\ $$