Question Number 90090 by john santu last updated on 21/Apr/20
$${xy}\:\frac{{dy}}{{dx}}\:=\:{y}^{\mathrm{2}} \:+\:\left(\frac{{x}^{\mathrm{3}} }{{x}^{\mathrm{2}} +\mathrm{1}}\right) \\ $$
Answered by john santu last updated on 21/Apr/20
xy-dy-dx-y-2-x-3-x-2-1-