Question Number 24631 by tawa tawa last updated on 23/Nov/17
Answered by ajfour last updated on 23/Nov/17
$${F}_{{max}} ={ma}_{{max}} ={m}\omega^{\mathrm{2}} {A}={kA} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:={m}\left(\frac{\mathrm{2}\pi}{{T}}\right)^{\mathrm{2}} {A}\: \\ $$$$\:\:\:=\mathrm{0}.\mathrm{12}×\frac{\mathrm{4}×\mathrm{9}.\mathrm{86}}{\mathrm{0}.\mathrm{04}}×\mathrm{0}.\mathrm{085}\:{N} \\ $$$$\:\:\:=\:\mathrm{10}{N} \\ $$$${k}=\frac{\mathrm{10}}{\mathrm{0}.\mathrm{085}}=\mathrm{118}{N}/{m}\:. \\ $$
Commented by tawa tawa last updated on 23/Nov/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$
Commented by tawa tawa last updated on 23/Nov/17
$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{sir} \\ $$