Question Number 90282 by 20000193 last updated on 22/Apr/20
$$\frac{\mathrm{1}}{\mathrm{2}\alpha+\beta}+\frac{\mathrm{1}}{\alpha+\mathrm{2}\beta} \\ $$
Commented by jagoll last updated on 22/Apr/20
$$\frac{\alpha+\mathrm{2}\beta+\mathrm{2}\alpha+\beta}{\left(\mathrm{2}\alpha+\beta\right)\left(\alpha+\mathrm{2}\beta\right)}\:=\:\frac{\mathrm{3}\alpha+\mathrm{3}\beta}{\mathrm{2}\alpha^{\mathrm{2}} +\mathrm{5}\alpha\beta+\mathrm{2}\beta^{\mathrm{2}} } \\ $$