Question Number 133300 by SEKRET last updated on 21/Feb/21
Commented by Dwaipayan Shikari last updated on 21/Feb/21
$${Diverges} \\ $$
Commented by mnjuly1970 last updated on 21/Feb/21
$$\:\:\int_{\mathrm{0}} ^{\:\infty} \frac{{ln}\left({x}\right)}{{e}^{{x}} }{dx}=−\gamma\:\left({euler}−{mascheroni}\right. \\ $$$$\left.\:\:{constant}\right) \\ $$$$\:{but}\:\int_{\mathrm{0}} ^{\:\infty} \frac{\mathrm{1}}{{e}^{{x}} {ln}\left({x}\right)}{dx}\:\:{is}\:{divergent}.. \\ $$
Answered by mnjuly1970 last updated on 21/Feb/21
