Question Number 25521 by Mahesh Andiboina last updated on 11/Dec/17
Answered by sushmitak last updated on 11/Dec/17
$$\mathrm{16} \\ $$$$\frac{{dy}}{{dx}}=\frac{{dy}/{dt}}{{dx}/{dt}}=\frac{\frac{{d}}{{dt}}\left(\mathrm{2}{at}\right)}{\frac{{d}}{{dt}}\left({at}^{\mathrm{2}} \right)}=\frac{\mathrm{2}{a}}{\mathrm{2}{at}}=\frac{\mathrm{1}}{{t}} \\ $$$$\mathrm{17} \\ $$$$\frac{{dy}}{{dx}}=\frac{{dy}/{dt}}{{dx}/{dt}}=\frac{\frac{{d}}{{dt}}\left({t}^{\mathrm{2}} −\mathrm{2}\right)}{\frac{{d}}{{dt}}\left(\mathrm{2}{t}+\mathrm{5}\right)}=\frac{\mathrm{2}{t}}{\mathrm{2}}={t} \\ $$