Menu Close

2-x-x-2-hence-x-2-prove-

Tinku Tara 0 Comments
Pin




Question Number 25787 by ibraheem160 last updated on 14/Dec/17
2^x =x^(2 ) ,hence x=2 . prove
$$\mathrm{2}^{{x}} ={x}^{\mathrm{2}\:} ,{hence}\:{x}=\mathrm{2}\:.\:{prove} \\ $$
Commented by mrW1 last updated on 14/Dec/17
It′s not true, Sir. If 2^x =x^2 ,then x=2 or x=4 or x=−0.77.
$${It}'{s}\:{not}\:{true},\:{Sir}. \\ $$$${If}\:\mathrm{2}^{{x}} ={x}^{\mathrm{2}} ,{then}\:{x}=\mathrm{2}\:{or}\:{x}=\mathrm{4}\:{or}\:{x}=−\mathrm{0}.\mathrm{77}. \\ $$
Commented by mrW1 last updated on 15/Dec/17
solution of 2^x =x^2 : if x>0: 2^(x/2) =x e^((xln 2)/2) =x 1=xe^(−((xln 2)/2)) −((ln 2)/2)=(−((xln 2)/2))×e^(−((xln 2)/2)) ⇒−((xln 2)/2)=W(−((ln 2)/2)) ⇒x=−((W(−((ln 2)/2)))/((ln 2)/2))=−((W(−ln (√2)))/(ln (√2))) if x<0: 2^(x/2) =−x e^((xln 2)/2) =−x 1=−xe^(−((xln 2)/2)) ((ln 2)/2)=(−((xln 2)/2))×e^(−((xln 2)/2)) ⇒−((xln 2)/2)=W(((ln 2)/2)) ⇒x=−((W(−((ln 2)/2)))/((ln 2)/2))=−((W(ln (√2)))/(ln (√2))) all together: ⇒x=−((W(±ln (√2)))/(ln (√2))) = { ((−((0.2657)/(0.3466))=−0.7666)),((−((−0.6932)/(0.3466))=2)),((−((1.3864)/(0.3466))=4)) :} in general the solution of a^x =x^n is x=−((W(−((ln a)/n)))/((ln a)/n)) or x=−((W(±((ln a)/n)))/((ln a)/n)) if n is even
$${solution}\:{of}\:\mathrm{2}^{{x}} ={x}^{\mathrm{2}} : \\ $$$$ \\ $$$${if}\:{x}>\mathrm{0}: \\ $$$$\mathrm{2}^{\frac{{x}}{\mathrm{2}}} ={x} \\ $$$${e}^{\frac{{x}\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}} ={x} \\ $$$$\mathrm{1}={xe}^{−\frac{{x}\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}} \\ $$$$−\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}=\left(−\frac{{x}\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}\right)×{e}^{−\frac{{x}\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}} \\ $$$$\Rightarrow−\frac{{x}\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}=\mathbb{W}\left(−\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}\right) \\ $$$$\Rightarrow{x}=−\frac{\mathbb{W}\left(−\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}\right)}{\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}}=−\frac{\mathbb{W}\left(−\mathrm{ln}\:\sqrt{\mathrm{2}}\right)}{\mathrm{ln}\:\sqrt{\mathrm{2}}} \\ $$$${if}\:{x}<\mathrm{0}: \\ $$$$\mathrm{2}^{\frac{{x}}{\mathrm{2}}} =−{x} \\ $$$${e}^{\frac{{x}\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}} =−{x} \\ $$$$\mathrm{1}=−{xe}^{−\frac{{x}\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}} \\ $$$$\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}=\left(−\frac{{x}\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}\right)×{e}^{−\frac{{x}\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}} \\ $$$$\Rightarrow−\frac{{x}\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}=\mathbb{W}\left(\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}\right) \\ $$$$\Rightarrow{x}=−\frac{\mathbb{W}\left(−\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}\right)}{\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}}=−\frac{\mathbb{W}\left(\mathrm{ln}\:\sqrt{\mathrm{2}}\right)}{\mathrm{ln}\:\sqrt{\mathrm{2}}} \\ $$$${all}\:{together}: \\ $$$$\Rightarrow{x}=−\frac{\mathbb{W}\left(\pm\mathrm{ln}\:\sqrt{\mathrm{2}}\right)}{\mathrm{ln}\:\sqrt{\mathrm{2}}} \\ $$$$=\begin{cases}{−\frac{\mathrm{0}.\mathrm{2657}}{\mathrm{0}.\mathrm{3466}}=−\mathrm{0}.\mathrm{7666}}\\{−\frac{−\mathrm{0}.\mathrm{6932}}{\mathrm{0}.\mathrm{3466}}=\mathrm{2}}\\{−\frac{\mathrm{1}.\mathrm{3864}}{\mathrm{0}.\mathrm{3466}}=\mathrm{4}}\end{cases} \\ $$$$ \\ $$$${in}\:{general}\:{the}\:{solution}\:{of} \\ $$$${a}^{{x}} ={x}^{{n}} \\ $$$${is}\:{x}=−\frac{\mathbb{W}\left(−\frac{{ln}\:{a}}{{n}}\right)}{\frac{\mathrm{ln}\:{a}}{{n}}} \\ $$$${or}\:{x}=−\frac{\mathbb{W}\left(\pm\frac{{ln}\:{a}}{{n}}\right)}{\frac{\mathrm{ln}\:{a}}{{n}}}\:{if}\:{n}\:{is}\:{even} \\ $$

Pin

Leave a Reply

Your email address will not be published. Required fields are marked *