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1-1-pi-2-n-2-1-n-1-n-1-2-1-pi-2-n-2-1-e-n-1-n-1-A-1-lt-2-B-1-2-C-1-gt-2-




Question Number 156900 by MathSh last updated on 16/Oct/21
Ω_1  = 1 - (π/2) +Σ_(n=2) ^∞ (- (1/𝛑))^n ∙ (1/(n+1))  Ω_2  = 1 - (π/2) + Σ_(n=2) ^∞ (- (1/e))^n ∙ (1/(n+1))  A) Ω_1  < Ω_2    B) Ω_1  = Ω_2    C) Ω_1  > Ω_2
$$\Omega_{\mathrm{1}} \:=\:\mathrm{1}\:-\:\frac{\pi}{\mathrm{2}}\:+\underset{\boldsymbol{\mathrm{n}}=\mathrm{2}} {\overset{\infty} {\sum}}\left(-\:\frac{\mathrm{1}}{\boldsymbol{\pi}}\right)^{\boldsymbol{\mathrm{n}}} \centerdot\:\frac{\mathrm{1}}{\mathrm{n}+\mathrm{1}} \\ $$$$\Omega_{\mathrm{2}} \:=\:\mathrm{1}\:-\:\frac{\pi}{\mathrm{2}}\:+\:\underset{\boldsymbol{\mathrm{n}}=\mathrm{2}} {\overset{\infty} {\sum}}\left(-\:\frac{\mathrm{1}}{\boldsymbol{\mathrm{e}}}\right)^{\boldsymbol{\mathrm{n}}} \centerdot\:\frac{\mathrm{1}}{\mathrm{n}+\mathrm{1}} \\ $$$$\left.\mathrm{A}\left.\right)\left.\:\Omega_{\mathrm{1}} \:<\:\Omega_{\mathrm{2}} \:\:\:\mathrm{B}\right)\:\Omega_{\mathrm{1}} \:=\:\Omega_{\mathrm{2}} \:\:\:\mathrm{C}\right)\:\Omega_{\mathrm{1}} \:>\:\Omega_{\mathrm{2}} \\ $$

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