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Question-26013




Question Number 26013 by tawa tawa last updated on 17/Dec/17
Answered by mrW1 last updated on 17/Dec/17
F_C +F_A sin 15°=F_B sin 75°  ⇒F_C =F_B sin 75°−F_A sin 15°  =2.1×sin 75°−2.3×sin 15°=1.43 KN    F_D =2.3×sin 75°−2.1×sin 15°=1.68 KN
$${F}_{{C}} +{F}_{{A}} \mathrm{sin}\:\mathrm{15}°={F}_{{B}} \mathrm{sin}\:\mathrm{75}° \\ $$$$\Rightarrow{F}_{{C}} ={F}_{{B}} \mathrm{sin}\:\mathrm{75}°−{F}_{{A}} \mathrm{sin}\:\mathrm{15}° \\ $$$$=\mathrm{2}.\mathrm{1}×\mathrm{sin}\:\mathrm{75}°−\mathrm{2}.\mathrm{3}×\mathrm{sin}\:\mathrm{15}°=\mathrm{1}.\mathrm{43}\:{KN} \\ $$$$ \\ $$$${F}_{{D}} =\mathrm{2}.\mathrm{3}×\mathrm{sin}\:\mathrm{75}°−\mathrm{2}.\mathrm{1}×\mathrm{sin}\:\mathrm{15}°=\mathrm{1}.\mathrm{68}\:{KN} \\ $$
Commented by tawa tawa last updated on 17/Dec/17
God bless you sir. i really appreciate.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}. \\ $$

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