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ax-2-bx-0-




Question Number 26042 by sanjib bibhar last updated on 18/Dec/17
ax^2 −bx=0
$${ax}^{\mathrm{2}} −{bx}=\mathrm{0} \\ $$
Commented by sanjib bibhar last updated on 19/Dec/17
thanks
$${thanks} \\ $$
Commented by Rasheed.Sindhi last updated on 18/Dec/17
ax^2 −bx=0  x(ax−b)=0  x=0 ∣ ax−b=0             ∣ x=(b/a)  ; a≠0
$${ax}^{\mathrm{2}} −{bx}=\mathrm{0} \\ $$$${x}\left({ax}−{b}\right)=\mathrm{0} \\ $$$${x}=\mathrm{0}\:\mid\:{ax}−{b}=\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\mid\:{x}=\frac{{b}}{{a}}\:\:;\:{a}\neq\mathrm{0} \\ $$

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