Question Number 91671 by M±th+et+s last updated on 02/May/20
$${show}\:{that} \\ $$$$\sqrt[{{ln}\left({x}\right)}]{{x}}={e} \\ $$
Commented by mr W last updated on 02/May/20
$$\sqrt[{{ln}\left({x}\right)}]{{x}}={x}^{\frac{\mathrm{1}}{\mathrm{ln}\:{x}}} ={e}^{\mathrm{ln}\:\left({x}^{\frac{\mathrm{1}}{\mathrm{ln}\:{x}}} \right)} ={e}^{\frac{\mathrm{1}}{\mathrm{ln}\:{x}}×\mathrm{ln}\:{x}} ={e}^{\mathrm{1}} ={e} \\ $$
Commented by M±th+et+s last updated on 02/May/20
$${nice}\:{work}\:{thank}\:{you} \\ $$