Question Number 26290 by d.monhbayr@gmail.com last updated on 23/Dec/17
$${f}\left({x}\right)=\mathrm{4}{x}^{\mathrm{2}} +\mathrm{1}\: \\ $$$${x}_{\mathrm{0}} =\mathrm{2} \\ $$
Commented by prakash jain last updated on 23/Dec/17
$${what}\:{is}\:{the}\:{questin} \\ $$$${f}\left({x}_{\mathrm{0}} \right)=\mathrm{4}×\mathrm{2}^{\mathrm{2}} +\mathrm{1}=\mathrm{17} \\ $$