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Question-157832




Question Number 157832 by mathlove last updated on 28/Oct/21
Answered by mr W last updated on 28/Oct/21
x^x^(3/2)  =x^x x^(x/2)   x^(x^(3/2) −((3x)/2)) =1  ⇒x=1  or  ⇒x^(3/2) −((3x)/2)=0  ⇒x^(3/2) =((3x)/2)  ⇒x^((3/2)−1) =(3/2)  ⇒x^(1/2) =(3/2)  ⇒x=(9/4)  summary:  x=1, (9/4)
$${x}^{{x}^{\frac{\mathrm{3}}{\mathrm{2}}} } ={x}^{{x}} {x}^{\frac{{x}}{\mathrm{2}}} \\ $$$${x}^{{x}^{\frac{\mathrm{3}}{\mathrm{2}}} −\frac{\mathrm{3}{x}}{\mathrm{2}}} =\mathrm{1} \\ $$$$\Rightarrow{x}=\mathrm{1} \\ $$$${or} \\ $$$$\Rightarrow{x}^{\frac{\mathrm{3}}{\mathrm{2}}} −\frac{\mathrm{3}{x}}{\mathrm{2}}=\mathrm{0} \\ $$$$\Rightarrow{x}^{\frac{\mathrm{3}}{\mathrm{2}}} =\frac{\mathrm{3}{x}}{\mathrm{2}} \\ $$$$\Rightarrow{x}^{\frac{\mathrm{3}}{\mathrm{2}}−\mathrm{1}} =\frac{\mathrm{3}}{\mathrm{2}} \\ $$$$\Rightarrow{x}^{\frac{\mathrm{1}}{\mathrm{2}}} =\frac{\mathrm{3}}{\mathrm{2}} \\ $$$$\Rightarrow{x}=\frac{\mathrm{9}}{\mathrm{4}} \\ $$$${summary}: \\ $$$${x}=\mathrm{1},\:\frac{\mathrm{9}}{\mathrm{4}} \\ $$
Commented by otchereabdullai@gmail.com last updated on 29/Oct/21
supper prof
$$\mathrm{supper}\:\mathrm{prof} \\ $$
Commented by mathlove last updated on 30/Oct/21
thanks sir
$${thanks}\:{sir}\: \\ $$

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