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Question-92356




Question Number 92356 by otchereabdullai@gmail.com last updated on 06/May/20
Commented by otchereabdullai@gmail.com last updated on 06/May/20
thanks for your time sir
$$\mathrm{thanks}\:\mathrm{for}\:\mathrm{your}\:\mathrm{time}\:\mathrm{sir} \\ $$
Commented by john santu last updated on 06/May/20
x=(√(t^2 −16^2 )) ⇒t^2 =x^2 +16^2   x=(√(y^2 −9^2 ))⇒y^2 =x^2 +81  y^2 +t^2 = 625 ← input   2x^2  = 288 ⇒x = 12 cm
$$\mathrm{x}=\sqrt{\mathrm{t}^{\mathrm{2}} −\mathrm{16}^{\mathrm{2}} }\:\Rightarrow\mathrm{t}^{\mathrm{2}} =\mathrm{x}^{\mathrm{2}} +\mathrm{16}^{\mathrm{2}} \\ $$$$\mathrm{x}=\sqrt{\mathrm{y}^{\mathrm{2}} −\mathrm{9}^{\mathrm{2}} }\Rightarrow\mathrm{y}^{\mathrm{2}} =\mathrm{x}^{\mathrm{2}} +\mathrm{81} \\ $$$$\mathrm{y}^{\mathrm{2}} +\mathrm{t}^{\mathrm{2}} =\:\mathrm{625}\:\leftarrow\:\mathrm{input}\: \\ $$$$\mathrm{2x}^{\mathrm{2}} \:=\:\mathrm{288}\:\Rightarrow\mathrm{x}\:=\:\mathrm{12}\:\mathrm{cm} \\ $$
Commented by john santu last updated on 06/May/20
short cut   x =(√(9×16)) = (√(144)) = 12 cm  if you find AB   AB = (√(9×25)) = 15 cm  AC = (√(16×25)) = 20 cm
$$\mathrm{short}\:\mathrm{cut}\: \\ $$$$\mathrm{x}\:=\sqrt{\mathrm{9}×\mathrm{16}}\:=\:\sqrt{\mathrm{144}}\:=\:\mathrm{12}\:\mathrm{cm} \\ $$$$\mathrm{if}\:\mathrm{you}\:\mathrm{find}\:\mathrm{AB}\: \\ $$$$\mathrm{AB}\:=\:\sqrt{\mathrm{9}×\mathrm{25}}\:=\:\mathrm{15}\:\mathrm{cm} \\ $$$$\mathrm{AC}\:=\:\sqrt{\mathrm{16}×\mathrm{25}}\:=\:\mathrm{20}\:\mathrm{cm}\: \\ $$
Commented by otchereabdullai@gmail.com last updated on 06/May/20
sir John am trying to understand the   first method but am confuse at   y^2 +t^(2 ) =625   please help me there
$$\mathrm{sir}\:\mathrm{John}\:\mathrm{am}\:\mathrm{trying}\:\mathrm{to}\:\mathrm{understand}\:\mathrm{the}\: \\ $$$$\mathrm{first}\:\mathrm{method}\:\mathrm{but}\:\mathrm{am}\:\mathrm{confuse}\:\mathrm{at}\: \\ $$$$\mathrm{y}^{\mathrm{2}} +\mathrm{t}^{\mathrm{2}\:} =\mathrm{625}\: \\ $$$$\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{there} \\ $$
Commented by john santu last updated on 06/May/20
AC = t ; AB=y  ∠A = 90^(o )   pytagorean theorem   t^2 +y^2  = (9+16)^2
$$\mathrm{AC}\:=\:\mathrm{t}\:;\:\mathrm{AB}=\mathrm{y} \\ $$$$\angle\mathrm{A}\:=\:\mathrm{90}^{\mathrm{o}\:} \\ $$$$\mathrm{pytagorean}\:\mathrm{theorem}\: \\ $$$$\mathrm{t}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} \:=\:\left(\mathrm{9}+\mathrm{16}\right)^{\mathrm{2}} \\ $$$$ \\ $$
Commented by otchereabdullai@gmail.com last updated on 06/May/20
ook!  so that 2x^2 =625−(16^2 +81)    thanks a lot sir
$$\mathrm{ook}!\:\:\mathrm{so}\:\mathrm{that}\:\mathrm{2x}^{\mathrm{2}} =\mathrm{625}−\left(\mathrm{16}^{\mathrm{2}} +\mathrm{81}\right)\:\: \\ $$$$\mathrm{thanks}\:\mathrm{a}\:\mathrm{lot}\:\mathrm{sir} \\ $$
Commented by john santu last updated on 06/May/20
most welcome
$$\mathrm{most}\:\mathrm{welcome} \\ $$

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