Question Number 158030 by VIDDD last updated on 30/Oct/21
$$\:\:\:\:{solve}\:{equation}\: \\ $$$$\:\:\:\mathrm{5}#+\left(\sqrt{\frac{\mathrm{5}!+\mathrm{5}}{\mathrm{5}!!+\mathrm{5}!!!}+!\mathrm{5}}−\mathrm{5}\right)\$=\mathrm{2}^{{x}} \\ $$
Commented by mkam last updated on 31/Oct/21
$${x}\:=\:\mathrm{5} \\ $$
Answered by mkam last updated on 31/Oct/21
