Question Number 27101 by Tinkutara last updated on 02/Jan/18
Answered by mrW1 last updated on 02/Jan/18
$${y}={ut}−\frac{\mathrm{1}}{\mathrm{2}}{gt}^{\mathrm{2}} =\mathrm{0} \\ $$$$\Rightarrow{t}=\frac{\mathrm{2}{u}}{{g}} \\ $$$${x}=\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} =\frac{\mathrm{2}{au}^{\mathrm{2}} }{{g}^{\mathrm{2}} } \\ $$$$\Rightarrow{Answer}\:\left(\mathrm{2}\right) \\ $$
Commented by Tinkutara last updated on 02/Jan/18
Thank you very much Sir! I got the answer.