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Question Number 2435 by Yozzi last updated on 20/Nov/15
Prove that                   Γ′(1)=∫_0 ^∞ e^(−x) lnxdx  is a negative number.
$${Prove}\:{that}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\Gamma'\left(\mathrm{1}\right)=\int_{\mathrm{0}} ^{\infty} {e}^{−{x}} {lnxdx} \\ $$$${is}\:{a}\:{negative}\:{number}. \\ $$
Commented by prakash jain last updated on 20/Nov/15
Γ′(1)=−γ  will add proof.
$$\Gamma'\left(\mathrm{1}\right)=−\gamma \\ $$$$\mathrm{will}\:\mathrm{add}\:\mathrm{proof}. \\ $$

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