Question Number 27334 by darkalestero1@gmail.com last updated on 05/Jan/18
$$\frac{\mathrm{q}_{\mathrm{1}} }{\mathrm{q}_{\mathrm{2}} }=\left(\frac{\mathrm{x}}{\mathrm{0}.\mathrm{8}−\mathrm{x}}\right)^{\mathrm{2}} \:\:\:\:;\:\boldsymbol{\mathrm{x}}=? \\ $$
Answered by mrW1 last updated on 05/Jan/18
$$\frac{{x}}{\mathrm{0}.\mathrm{8}−{x}}=\pm\sqrt{\frac{{q}_{\mathrm{1}} }{{q}_{\mathrm{2}} }} \\ $$$$\frac{\mathrm{0}.\mathrm{8}−{x}}{{x}}=\pm\sqrt{\frac{{q}_{\mathrm{2}} }{{q}_{\mathrm{1}} }} \\ $$$$\frac{\mathrm{0}.\mathrm{8}}{{x}}=\mathrm{1}\pm\sqrt{\frac{{q}_{\mathrm{2}} }{{q}_{\mathrm{1}} }} \\ $$$$\Rightarrow{x}=\frac{\mathrm{0}.\mathrm{8}}{\mathrm{1}\pm\sqrt{\frac{{q}_{\mathrm{2}} }{{q}_{\mathrm{1}} }}} \\ $$