Question Number 27618 by NECx last updated on 11/Jan/18
$${Find}\:{the}\:{range}\:{of}\:{y}={x}\left({x}^{\mathrm{6}} −\mathrm{1}\right).{For} \\ $$$${which}\:{y}=\mathrm{0} \\ $$
Answered by mrW2 last updated on 13/Jan/18
$${y}={x}\left({x}^{\mathrm{6}} −\mathrm{1}\right)=\mathrm{0} \\ $$$$\Rightarrow{x}=\mathrm{0} \\ $$$$\Rightarrow{x}^{\mathrm{6}} =\mathrm{1}\Rightarrow{x}=\pm\mathrm{1} \\ $$$$\Rightarrow{x}\in\left\{−\mathrm{1},\mathrm{0},\mathrm{1}\right\} \\ $$
Commented by NECx last updated on 13/Jan/18
$${thanks}\:{so}\:{much} \\ $$