Question Number 159180 by cortano last updated on 14/Nov/21
Answered by som(math1967) last updated on 14/Nov/21
$${HI}=\mathrm{50}{tan}\mathrm{48}=\mathrm{55}.\mathrm{53} \\ $$$${HL}=\mathrm{55}.\mathrm{53}+\mathrm{40}=\mathrm{95}.\mathrm{53} \\ $$$${LQ}=\mathrm{50}+\mathrm{8}=\mathrm{58} \\ $$$${HQ}=\sqrt{\mathrm{58}^{\mathrm{2}} +\left(\mathrm{95}.\mathrm{53}\right)^{\mathrm{2}} }=\mathrm{111}.\mathrm{75}\:{feet}\left({approx}\right) \\ $$
Commented by som(math1967) last updated on 14/Nov/21
Commented by Rasheed.Sindhi last updated on 14/Nov/21
$${Why}\:{has}\:{Mr}\:{Cortano}\:{added}\:{blue} \\ $$$${rectangle}\:{in}\:{his}\:{figure}.{It}'{s}\:{of}\:{no} \\ $$$${use}!!! \\ $$