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Question-159345




Question Number 159345 by akolade last updated on 15/Nov/21
Answered by Ar Brandon last updated on 15/Nov/21
5^((y/2)+3) =125(5^(y/2) )=125(5^y )^(1/2)   =125(36)^(1/2) =125×6=750
5y2+3=125(5y2)=125(5y)12=125(36)12=125×6=750
Commented by akolade last updated on 15/Nov/21
cool sir
coolsir
Answered by yeti123 last updated on 16/Nov/21
5^y  = 36  y = log_5  36    x = 5^((y/2) + 3)   log_5  x = log_5  (5^((y/2) + 3) )               = ((y/2) + 3) log_5  5               = (y/2) + 3               = (1/2)log_5  36 + 3               = log_5  36^(1/2)  + log_5  5^3                = log_5  6 + log_5  125               = log_5  (6×125)        x    = 6×125               = 750
5y=36y=log536x=5y2+3log5x=log5(5y2+3)=(y2+3)log55=y2+3=12log536+3=log5361/2+log553=log56+log5125=log5(6×125)x=6×125=750

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