Question Number 159447 by mnjuly1970 last updated on 17/Nov/21

Commented by Ar Brandon last updated on 17/Nov/21

Answered by Ar Brandon last updated on 17/Nov/21
![Ω=∫_0 ^1 ∫_0 ^1 ((x^(t/2) −x^t )/(1−x))dxdt =∫_0 ^1 (ψ(t+1)−ψ((t/2)+1))dt =[ln(Γ(t+1))−2ln(Γ((t/2)+1))]_0 ^1 =ln(((Γ(2))/(Γ^2 ((3/2)))))−ln(((Γ(1))/(Γ^2 (1))))=ln((4/π))](https://www.tinkutara.com/question/Q159451.png)
Commented by mnjuly1970 last updated on 17/Nov/21

Commented by Ar Brandon last updated on 17/Nov/21
With you too, Sir.