Question Number 95967 by pticantor last updated on 29/May/20
Commented by pticantor last updated on 29/May/20
$${please}\:{i}\:{need}\:{help}\:{please}\:{please} \\ $$
Answered by john santu last updated on 29/May/20
$$\left(\mathrm{1}\right)\sqrt{\mathrm{5}−{a}}\:=\:\mathrm{4}−{a}^{\mathrm{2}} \\ $$$$\mathrm{5}−{a}\:=\:\mathrm{16}−\mathrm{8}{a}^{\mathrm{2}} +{a}^{\mathrm{4}} \\ $$$${a}^{\mathrm{4}} −\mathrm{8}{a}^{\mathrm{2}} +{a}+\mathrm{11}=\mathrm{0} \\ $$$${let}\:{a}\:=\:{x}\:\Rightarrow{x}^{\mathrm{4}} −\mathrm{8}{x}^{\mathrm{2}} +{x}+\mathrm{11}=\mathrm{0} \\ $$
Commented by pticantor last updated on 29/May/20
$${thank}\:{you}\:!! \\ $$$$\boldsymbol{{please}}\:\boldsymbol{{could}}\:\boldsymbol{{you}}\:\boldsymbol{{help}}\:\boldsymbol{{me}}\:\boldsymbol{{with}} \\ $$$$\boldsymbol{{a}}\:\boldsymbol{{third}}\:\boldsymbol{{question}}\:?? \\ $$