Question Number 96538 by Hamida last updated on 02/Jun/20
Answered by john santu last updated on 02/Jun/20
$$\mathrm{y}'=\frac{\mathrm{2}.\mathrm{7}−\mathrm{2}.\mathrm{8}}{\left(\mathrm{8x}+\mathrm{7}\right)^{\mathrm{2}} }\:=\:−\frac{\mathrm{2}}{\left(\mathrm{8x}+\mathrm{7}\right)^{\mathrm{2}} } \\ $$
Commented by Hamida last updated on 02/Jun/20
$${how}\:{it}\:{is}\:{become}\:\mathrm{2}.\mathrm{7}−\mathrm{2}.\mathrm{8} \\ $$
Commented by john santu last updated on 02/Jun/20
$$\mathrm{in}\:\mathrm{generally}\:\mathrm{if}\: \\ $$$$\mathrm{y}=\frac{{ax}+{b}}{{cx}+{d}}\:\Rightarrow\:\mathrm{y}'=\frac{{a}.{d}−{b}.{c}}{\left({cx}+{d}\right)^{\mathrm{2}} } \\ $$
Commented by Hamida last updated on 02/Jun/20
$${Thank}\:{you}\: \\ $$$$ \\ $$