Question-96548

Question Number 96548 by Hamida last updated on 02/Jun/20

Commented by bobhans last updated on 02/Jun/20

$$\mathrm{y}'=−\mathrm{6e}^{−\mathrm{6x}} \:+\:\mathrm{8}\:\mathrm{cos}\:\mathrm{8x}\:\ldots\ldots\ldots \\ $$