Question Number 162229 by Tawa11 last updated on 27/Dec/21
Answered by mr W last updated on 28/Dec/21
$${u}_{{X}} ={speed}\:{of}\:{gear}\:{X} \\ $$$${t}_{{X}} ={torque}\:{of}\:{gear}\:{X} \\ $$$${u}_{{D}} =\mathrm{200}\:{rpm}\:\curvearrowright \\ $$$${t}_{{D}} =\mathrm{15}\:{Nm} \\ $$$$ \\ $$$${u}_{{C}} =\frac{\mathrm{20}}{\mathrm{10}}×{n}_{{D}} =\mathrm{2}{u}_{{D}} =\mathrm{400}\:{rpm}\:\curvearrowleft \\ $$$${u}_{{B}} ={u}_{{C}} =\mathrm{400}\:{rpm}\:\curvearrowleft \\ $$$${u}_{{A}} =\frac{\mathrm{20}}{\mathrm{10}}×{n}_{{B}} =\mathrm{2}{u}_{{B}} =\mathrm{800}\:{rpm}\:\curvearrowright \\ $$$$ \\ $$$${the}\:{torque}\:{on}\:{the}\:{gears}\:{can}\:{not}\:{be}\: \\ $$$${determined}\:{according}\:{to}\:{my}\: \\ $$$${understanding}. \\ $$$${please}\:{ask}\:{your}\:{teacher}\:{what}\:{is} \\ $$$${meat}\:{here}! \\ $$
Commented by Tawa11 last updated on 28/Dec/21
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{more}. \\ $$