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find-0-1-t-2-arctant-1-t-4-dt-

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Question Number 31419 by abdo imad last updated on 08/Mar/18
find ∫_0 ^∞ (((1+t^2 )arctant)/(1+t^4 ))dt .
$${find}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{\left(\mathrm{1}+{t}^{\mathrm{2}} \right){arctant}}{\mathrm{1}+{t}^{\mathrm{4}} }{dt}\:. \\ $$

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