Question Number 162734 by Eric002 last updated on 31/Dec/21
![Happy New Year [(10+9)×8×(7+6)+(5+4)×(3+2)+1]](https://www.tinkutara.com/question/Q162734.png)
$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{Happy}\:{New}\:{Year} \\ $$$$\left[\left(\mathrm{10}+\mathrm{9}\right)×\mathrm{8}×\left(\mathrm{7}+\mathrm{6}\right)+\left(\mathrm{5}+\mathrm{4}\right)×\left(\mathrm{3}+\mathrm{2}\right)+\mathrm{1}\right] \\ $$
Answered by alephzero last updated on 01/Jan/22
![Happy New Year Too!!! [(10 + 9)8(7 + 6) + (5 + 4)(3 + 2) + 1] = [19 × 8 × 13 + 9 × 5 + 1] = 1976 + 45 + 1 = 2022 Happy 2022!](https://www.tinkutara.com/question/Q162795.png)
$$\underline{{Happy}\:{New}\:{Year}\:{Too}!!!} \\ $$$$\left[\left(\mathrm{10}\:+\:\mathrm{9}\right)\mathrm{8}\left(\mathrm{7}\:+\:\mathrm{6}\right)\:+\:\left(\mathrm{5}\:+\:\mathrm{4}\right)\left(\mathrm{3}\:+\:\mathrm{2}\right)\:+\:\mathrm{1}\right]\:= \\ $$$$\left[\mathrm{19}\:×\:\mathrm{8}\:×\:\mathrm{13}\:+\:\mathrm{9}\:×\:\mathrm{5}\:+\:\mathrm{1}\right]\:= \\ $$$$\mathrm{1976}\:+\:\mathrm{45}\:+\:\mathrm{1}\:=\:\mathrm{2022} \\ $$$$\underline{{Happy}\:\mathrm{2022}!} \\ $$