calcul-en-fonction-de-n-k-0-2n-k-2n-n-2k-

Tinku Tara June 4, 2023 None 0 Comments

Question Number 163024 by SANOGO last updated on 03/Jan/22

calcul en fonction de n Σ_(k=0) ^(2n) (_k ^(2n) )^(n−2k)

$${calcul}\:{en}\:{fonction}\:{de}\:{n} \\ $$$$\underset{{k}=\mathrm{0}} {\overset{\mathrm{2}{n}} {\sum}}\left(_{{k}} ^{\mathrm{2}{n}} \right)^{{n}−\mathrm{2}{k}} \\ $$

Commented by SANOGO last updated on 03/Jan/22

$${i}'{m}\:{sur}\:{sir} \\ $$

Commented by mr W last updated on 03/Jan/22

$${are}\:{you}\:{sure}\:{there}\:{is}\:{no}\:{typo}? \\ $$

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